Topic: Quazar ejections | |
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Quasars are always associated with supermassive Black Holes at the center's of most Galaxies, not all supermassive's have one, and the theory goes that they happen when the central Black Hole is "feeding". When enough material is falling into that Black hole, and it's outside the Event Horizon where gravity's still too weak to compress it inward, there's then too much congestion to allow it all to fall inward, that material is then "burped" outward. This is where the "mystery" lies, it seems physicists don't understand why those ejections occur at the poles, the Galactic axis. Maybe I'm oversimplifying, but no Black Hole will have a perfectly round Singularity, solely for the fact that time inside a Black Hole comes to a virtual standstill - this means the actual Singularity is disc-shaped, the majority of the Singularity's mass is at it's equator, slowly falling inward from the outer accretion disk. In other words, a Black Hole's weakest gravitational point will be at it's axis, where the least material is falling inward inside the Event Horizon. It's obvious to me, that's why Quasars eject at the Galactic axis. Curious if anyone, specifically anyone who works this field, has any thoughts? |
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Edited by
Dramatic Muffin
on
Sun 09/26/21 04:59 PM
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Time dilation as it affects the shape of a singularity, interesting, maybe mainstream physics missed a small detail...
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Pretty and smart!
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You bring out the best in me, Mark.
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You bring out the best in me, Mark. LOL, sure, that's it! |
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Quasars are always associated with supermassive Black Holes at the center's of most Galaxies, not all supermassive's have one, and the theory goes that they happen when the central Black Hole is "feeding". When enough material is falling into that Black hole, and it's outside the Event Horizon where gravity's still too weak to compress it inward, there's then too much congestion to allow it all to fall inward, that material is then "burped" outward. This is where the "mystery" lies, it seems physicists don't understand why those ejections occur at the poles, the Galactic axis. Maybe I'm oversimplifying, but no Black Hole will have a perfectly round Singularity, solely for the fact that time inside a Black Hole comes to a virtual standstill - this means the actual Singularity is disc-shaped, the majority of the Singularity's mass is at it's equator, slowly falling inward from the outer accretion disk. In other words, a Black Hole's weakest gravitational point will be at it's axis, where the least material is falling inward inside the Event Horizon. It's obvious to me, that's why Quasars eject at the Galactic axis. Curious if anyone, specifically anyone who works this field, has any thoughts? Hi Mark I recall discussing my thoughts on "Black" "Holes" on a previous thread. http://mingle2.com/topic/589961 You might find what I wrote interesting? A "Black Hole" is neither black or a hole.
Consider what we understand about star formation.
On a different thread I also commented http://mingle2.com/topic/587684 And again on a different thread http://mingle2.com/topic/539685 As material is pulled onto the singularity it strikes the singularity unevenly around the center (Equator) of the mass. This causes the singularity to spin (Just like the Sun and the Earth spin from their accretion). The Poles of the singularity have less active mass accretion compared to its equator. Thus, the high gamma radiation is expelled from its poles as jets (Just like the Earth's magnetosphere is pole to pole). This high emission of radiation is so forceful it sends the radiation out into space as long detectable jets. The jets are longer or shorter determined from the amount of mass being collected. A singularity that is gathering less mass has jets that are being redirected back onto the singularity before it can escape the event horizon.
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You bring out the best in me, Mark. LOL, sure, that's it! Just a cordial jolt of reality....THIS IS Theoretical Physics and is as Equally Proven, Replicable and Standardized ... ... as ... ...Darwinian Theory! |
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Quasars are always associated with supermassive Black Holes at the center's of most Galaxies, not all supermassive's have one, and the theory goes that they happen when the central Black Hole is "feeding". When enough material is falling into that Black hole, and it's outside the Event Horizon where gravity's still too weak to compress it inward, there's then too much congestion to allow it all to fall inward, that material is then "burped" outward. This is where the "mystery" lies, it seems physicists don't understand why those ejections occur at the poles, the Galactic axis. Maybe I'm oversimplifying, but no Black Hole will have a perfectly round Singularity, solely for the fact that time inside a Black Hole comes to a virtual standstill - this means the actual Singularity is disc-shaped, the majority of the Singularity's mass is at it's equator, slowly falling inward from the outer accretion disk. In other words, a Black Hole's weakest gravitational point will be at it's axis, where the least material is falling inward inside the Event Horizon. It's obvious to me, that's why Quasars eject at the Galactic axis. Curious if anyone, specifically anyone who works this field, has any thoughts? Hi Mark I recall discussing my thoughts on "Black" "Holes" on a previous thread. http://mingle2.com/topic/589961 You might find what I wrote interesting? A "Black Hole" is neither black or a hole.
Consider what we understand about star formation.
On a different thread I also commented http://mingle2.com/topic/587684 And again on a different thread http://mingle2.com/topic/539685 As material is pulled onto the singularity it strikes the singularity unevenly around the center (Equator) of the mass. This causes the singularity to spin (Just like the Sun and the Earth spin from their accretion). The Poles of the singularity have less active mass accretion compared to its equator. Thus, the high gamma radiation is expelled from its poles as jets (Just like the Earth's magnetosphere is pole to pole). This high emission of radiation is so forceful it sends the radiation out into space as long detectable jets. The jets are longer or shorter determined from the amount of mass being collected. A singularity that is gathering less mass has jets that are being redirected back onto the singularity before it can escape the event horizon.
Hi Tom, it's easy to see why you were missed when you were out ill.... My premise does not debate the existence of Black holes, worm holes or white holes, but only proposes a theory on why Quazar jets expel from galactic axis's of Sumpermassive's. |
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Yeah, I get that.
Perhaps it has to do with the way stars form in the Universe? As you said, the poles have slightly weaker gravity than the equator. This is common for all things which acreate mass. It also explains why things in the Universe spin. If you think about how stars form from dust and gas, grow in mass until they ignite it makes it a simple fact there would be emission from the poles. All stars have some type of discharge from their poles. Black Holes and Quasars have the high energy to produce gamma discharge at their poles. |
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A star works by fusion. When the mass is large enough 2 molecules of hydrogen will fuse together making 1 molecule of helium. This is a nuclear process and is what causes the sun to be so hot. This process can only go as high as iron. Any element beyond can only be produced when a star nova's.
The sun cannot ignite as there is no oxygen in outer space. The poles of the earth have slightly weaker gravity than the equator because like you are saying about the sun, the earths equator bulges giving more mass thus more gravity. I have never thought about the sun having more mass at it's equator, perhaps this is why the solar systems planets go around in a plane. Interesting. Thank you. |
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A star works by fusion. When the mass is large enough 2 molecules of hydrogen will fuse together making 1 molecule of helium. This is a nuclear process and is what causes the sun to be so hot. This process can only go as high as iron. Any element beyond can only be produced when a star nova's. The sun cannot ignite as there is no oxygen in outer space. The poles of the earth have slightly weaker gravity than the equator because like you are saying about the sun, the earths equator bulges giving more mass thus more gravity. I have never thought about the sun having more mass at it's equator, perhaps this is why the solar systems planets go around in a plane. Interesting. Thank you. The sun doesn't have more mass it the equator. I only mention that a Black Hole would, due to time dilation matter moving inside a Black Hole is at a near stand still, meaning matter falling from it's accretion disk causes the singularity to be disc shaped. |
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Seems to me a black hole (white singularity) would be a spinning single particle of matter.
Granted nobody knows for sure because we can't observe, measure or test the singularity directly. However, reasonable logic indicates a single particle of matter which is spinning. Here's why I believe this is true: Stars have massive gravity. The more massive the star, the more gravity it has. Neutron stars have a radius on the order of 10 kilometres (6.2 mi) and a mass of about 1.4 solar masses. They result from the supernova explosion of a massive star, combined with gravitational collapse, that compresses the core past white dwarf star density to that of atomic nuclei. A neutron star is the collapsed core of a massive supergiant star, which had a total mass of between 10 and 25 solar masses, possibly more if the star was especially metal-rich. Except for black holes, and some hypothetical objects, neutron stars are the smallest and densest currently known class of stellar objects. Just a sugar cube of neutron star matter would weigh about one hundred million tons on Earth. The atoms of a neutron star are tightly packed together from the effects of gravity which caused them. Ramp that gravity up to black hole (white singularity) stage and the gravitational effects exceed the atomic stability of atoms within its effect. At some point, the atoms fuse into a single particle which is known as a singularity. The black hole (white singularity) becomes a single immense mass. This single particle is immensely hot and massive creating huge gravitation effects on surrounding space. As mass gets attracted to the spinning singularity, it collects in a disc around the singularity until it falls onto and is absorbed into the mass of the singularity. This means as mass is added to the singularity from a spinning disc, it collects onto the spinning equator of the singularity. Depending upon the amount of mass reaching the singularity's equator, the mass at the equator rises and falls as the mass being added is absorbed. This means at certain times, depending on the amount of 'food' it eats, the black hole (white singularity) is slightly more massive at its equator. However, this effect is short lived because all added mass increases the single particle of the singularity. A black hole eating a star will have a higher mass at its equator than a black hole eating a planet. Sagittarius A (the super-massive black hole at the center of the Milky Way) has a constant supply of material being absorbed to its singularity so would in fact have more mass at its equator. Theoretical 'Wandering' supermassive black holes (those that don't lie at their galaxies' centers) have less mass to eat so are equally massive over the entire singularity. Similar to smaller rogue black holes moving thru a galaxy. These types of black holes also do not possess gamma ray jets at their poles (at least not like supermassive black holes). The size of mass in a black hole dictates whether or not it shows a gamma ray jet. This is because there is a threshold for energy expulsion. Energy is mass-less, so is light (sometimes). Gamma is light energy. Up until a certain point the mass of the singularity exceeds the ability of light energy to escape. During low consumption periods, the conversion process of turning mass collected into singularity can't exceed the gravitational effects of the mass. As new material is converted to singularity, the energy increases and at some unknown limit, the energy is expelled at the poles because the consumption process increases the mass at the equator beyond the energy's escape threshold. The poles, having less mass, creates a relative weak point which allows the high energy to escape the gravity well. But, this only happens as the singularity is accumulating more mass at great density. As the black hole starts to starve, the mass of the singularity equalizes in the particle and the gamma ray jets shut off. Its the process of eating and growing which causes gamma ray jets at the singularity's equator. Remove that process and the energy can't escape the gravity. What makes sense to me, the singularity is a single massive particle, not a collection of mass particles like a star. The fusion process causes high energy. The fusion process is not spherical but equatorial. Only when the fusion process falls off does the singularity equalize to spherical. The fusion process is directly related to the amount of material being absorbed. The new mass is collected onto the singularity at its equator, increasing the mass at the equator. The fusion process of making that additional mass part of the singularity builds at the higher mass equator and moves towards the singularity poles, which are relatively of lower mass during the accumulation process. With higher mass at the equator and lower mass at the poles the gravitational forces are lower at the poles to the point the high fusion energy can exceed the gravity and be expelled. When the mass induction diminishes to an unknown value, the gravity equalizes and the jets shut off. Not only because the gravity equalizes but also because with less material being converted, less fusion energy is being released. When many people think "particle" they think quantum or very small particles. However, any singularity is a single particle and the size of a particle is directly related to its mass. All particles have mass, charge and spin except the Force Carriers (vector & scalar bosons) The black hole has mass and spin and the fusion energy dictates its charge. Mass at quantum levels is measured in electron volts. 1 keV = 103 eV 1 MeV = 106 eV 1 GeV = 109 eV and 1 TeV = 1012 eV(hence the Tevatron) As far as I know there is no scale to measure or standardize the mass, charge & spin of black holes. Probably because there is no way we can measure it precisely. The singularity does have a charge (released as gamma ray jets) but the charge is not constant and no precise measurements can be done. I'm pretty sure the swirling accumulation of mass creates a charge as well as the fusion process itself, not to ignore the equalizing process within the singularity and the resultant expulsion process. I also believe the matter being absorbed is striped of its force carriers as part of the released energy in the gamma jets. But, there's no way we can measure the boson content of a gamma jet. There must be Higgs bosons present which keep the jets confined within the speed of light otherwise there would be no 'jets' and the energy would fly off in all directions at the speed of light (we wouldn't be able to see them). Anyway, this is what makes sense to me but then, I'm not a scientist, I'm a disable truck mechanic with too much time on my hands. |
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