Solve this and get my 5 digit password...but has d following details

1. The first digit ȋ̝̊̅ڪ the square of the 2nd
2. The sum of the 2nd and 3rd digits is 10
3. the 4th digit ȋ̝̊̅ڪ the 2nd digit plus 1
4. The sum of the 5th and 3rd digit is 14
5. And finally, the sum of all the digits is 30

Am solving this myself
but dont log into my account
a=b2(square of b)
c=10-b(if b+c=10)
d=b+1
e=14-(10-b)----->(from c=10-b)
;e=14-10+b(if you multiply through be -)
e=4+b


Since a+b+c+d+e=30
therefore using the simplification above

b2+b+(10-b)+(b+1)+(4+b)=30

b2+b+10-b+b+1+4+b=30

b2+2b+10+1+4=30
b2+2b+15=30

b2+2b=30-15
b2+2b=15

b2+2b-15=0(quadratic equation)

(b-3)(b+5)=0

b=3 0r -5...we're dealing with +ve nos so -5 is ruled out so b=3

with that knowledge put b=3 back in the info

a=32=9
b=3
c is 10-3=7
d is 3+1=4
e is 4+3=7
digits are 9,3,7,4,7 tongue