Community > Dating & Relationships

Topic: Age range
Spidercmb Joined Fri 04/27/07 Posts: 13137	Fri 01/27/12 05:03 PM
... You only have a 1/3 probability of being correct with each couple. That means out of the first 3 couples the Law of Probability says you get 1 correct. That is 3 out of 9 .. 33%... Even if the last couple is a father/ daughter that is 40%.. The chances of that last couple being father/ daughter is 11% so I say its more like 3/10 for 30%.. Now unless you want to tell me psychology trumps mathematics I suggest you recant your claim of "You know I am correct and don't want to admit it". What do you mean by "You only have a 1/3 probability of being correct with each couple."?

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 05:07 PM
... You only have a 1/3 probability of being correct with each couple. That means out of the first 3 couples the Law of Probability says you get 1 correct. That is 3 out of 9 .. 33%... Even if the last couple is a father/ daughter that is 40%.. The chances of that last couple being father/ daughter is 11% so I say its more like 3/10 for 30%.. Now unless you want to tell me psychology trumps mathematics I suggest you recant your claim of "You know I am correct and don't want to admit it". What do you mean by "You only have a 1/3 probability of being correct with each couple."? you have 3 potential outcomes.. 1. father daughter 2. married 3. dating the assumption is that all 10 couples are father daughter.. 1 assumption/ 3 potential outcomes 33% probability for each couple of being father daughter.. Its not complicated..

patsfan64 Joined Fri 03/14/08 Posts: 1258	Fri 01/27/12 05:16 PM
I try to stick within the 5-7 minute range. That's each way of course. I wouldn't want to miss out on someone slightly younger if I ever did date again.

Spidercmb Joined Fri 04/27/07 Posts: 13137	Fri 01/27/12 05:16 PM
you have 3 potential outcomes.. 1. father daughter 2. married 3. dating the assumption is that all 10 couples are father daughter.. 1 assumption/ 3 potential outcomes 33% probability for each couple of being father daughter.. Its not complicated.. Actually, there are more possibilities than those three, but your problem isn't the number of possibilities, it's the weighting. For your chances to be 1 in 3, it would have to be equally likely that a young woman would: 1) Eat lunch with her father 2) Marry a man who was old enough to be her father 3) Date a man who was old enough to be her father. It's clearly much more likely that a young woman would be having lunch with her father, so giving equal weight to the other possibilities is ludicrous.

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 05:28 PM
you have 3 potential outcomes.. 1. father daughter 2. married 3. dating the assumption is that all 10 couples are father daughter.. 1 assumption/ 3 potential outcomes 33% probability for each couple of being father daughter.. Its not complicated.. Actually, there are more possibilities than those three, but your problem isn't the number of possibilities, it's the weighting. For your chances to be 1 in 3, it would have to be equally likely that a young woman would: 1) Eat lunch with her father 2) Marry a man who was old enough to be her father 3) Date a man who was old enough to be her father. It's clearly much more likely that a young woman would be having lunch with her father, so giving equal weight to the other possibilities is ludicrous. No.. No.. No.. you specifically laid out 3 possibilities. You can't start making things up now.. "If you assumed that those 10 couples were father and daughter, I submit that you would be right more than 50% of the time." "they are dating" "If you generally think that people don't publicly cheat, you might assume that they are married to one another." 1. Father/daughter 2. Dating 3. Married Those are the 3 potential outcomes from your original post. Mathematically your more than 50% correct that these couples are father and daughter is NOT probable.. You can write 5000 paragraphs explaining one hundred thousand new variables, but it doesn't change your original post that you accused me of dodging and not willing to admit your above 50% claim was correct.. You can go on with this charade, or you can admit that based on your original post and what it contained you are NOT correct.. Its that simple..

Spidercmb Joined Fri 04/27/07 Posts: 13137	Fri 01/27/12 05:46 PM
No.. No.. No.. you specifically laid out 3 possibilities. You can't start making things up now.. "If you assumed that those 10 couples were father and daughter, I submit that you would be right more than 50% of the time." "they are dating" "If you generally think that people don't publicly cheat, you might assume that they are married to one another." 1. Father/daughter 2. Dating 3. Married Those are the 3 potential outcomes from your original post. Mathematically your more than 50% correct that these couples are father and daughter is NOT probable.. You can write 5000 paragraphs explaining one hundred thousand new variables, but it doesn't change your original post that you accused me of dodging and not willing to admit your above 50% claim was correct.. You can go on with this charade, or you can admit that based on your original post and what it contained you are NOT correct.. Its that simple.. I'm sorry, I believe that I already explained this. The problem you have isn't in the number of possibilities, it's in the weighting. All of the possibilities are not equally probably. Here's an example: Everybody with two hands is either: a) right handed b) left handed c) ambidextrous The probability that someone is right handed is between 70-90%. So if you guessed that everyone you met was right handed, you would be right more than 50% of the time. It's the same in my hypothetical scenario, it's much more likely that the pair is father/daughter than either of the other two possibilities listed. Don't forget, we are talking about a couple with enough years between them for the male to be mistaken for the female's father.

Chloe23Irish Joined Sun 01/01/12 Posts: 717	Fri 01/27/12 05:56 PM
Meh :/ I don't think about it really. I'll cross that bridge if or when I get to it.

sweetestgirl11 Joined Fri 09/12/08 Posts: 30087	Fri 01/27/12 06:01 PM
I don't really have any set limits. If it works, it works. I'd never turn something that worked away just because the numbers don't match. I like this, shannon!

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 06:02 PM
No.. No.. No.. you specifically laid out 3 possibilities. You can't start making things up now.. "If you assumed that those 10 couples were father and daughter, I submit that you would be right more than 50% of the time." "they are dating" "If you generally think that people don't publicly cheat, you might assume that they are married to one another." 1. Father/daughter 2. Dating 3. Married Those are the 3 potential outcomes from your original post. Mathematically your more than 50% correct that these couples are father and daughter is NOT probable.. You can write 5000 paragraphs explaining one hundred thousand new variables, but it doesn't change your original post that you accused me of dodging and not willing to admit your above 50% claim was correct.. You can go on with this charade, or you can admit that based on your original post and what it contained you are NOT correct.. Its that simple.. I'm sorry, I believe that I already explained this. The problem you have isn't in the number of possibilities, it's in the weighting. All of the possibilities are not equally probably. Here's an example: Everybody with two hands is either: a) right handed b) left handed c) ambidextrous The probability that someone is right handed is between 70-90%. So if you guessed that everyone you met was right handed, you would be right more than 50% of the time. It's the same in my hypothetical scenario, it's much more likely that the pair is father/daughter than either of the other two possibilities listed. Don't forget, we are talking about a couple with enough years between them for the male to be mistaken for the female's father. You have 10 sets of men and women sitting at a table together.. Older men Younger women. You assume all 10 are father/daughter. You see kissing.. You see wedding rings.. Dates unmarried couples. Married couples.. Law of Probability.. All 10 couples are independent variables.. The equation for this is.. P/A variable x P/B variable x P/C variable.. If you flip 1 coin and assume it will land heads up that is 1/2 or a 50% probability.. If you flip 2 coins and you assume they will both land heads up that is 1/2 x 1/2 = 1/4 or a 25% probability.. Assuming a man and a woman sitting at a table can be one of three things and you deduce that they are a father daughter that is 1 the assumed relationship/ 3 possible relationships.. That is 33%...

wux Joined Wed 07/29/09 Posts: 7426	Fri 01/27/12 06:04 PM
biological age is not as much a factor as emotional age, so the only distinctions I make is(out of consideration for my children), I wont go out with anyone born in the 80's or since, as my eldest was born in the early 90s and it would be too strange and unfair for him to have to see one of his peers as a 'stepfather' ... or to see his own mother as a sex-bewildered galvanized Galvanian woman. Because, incidentally or not, I did that to a woman. I dated her mother, and the woman was exactly a year younger than I, more or less. Julia, that little bratty nip, never called me "Father" or "Daddy", but in retrospect I blame myself, because it could have been different if I married her mother and adopted Julia. She called me father just once... she was drunk, her mom and I just came home drunk, and she was there, playing mama-papa with her boyfriend, and she lost it, she screamed at me, and one of the words she used was "...AND YOU MOTHER-FATHER, WHY DID YOU NOT...etc."

Chloe23Irish Joined Sun 01/01/12 Posts: 717	Fri 01/27/12 06:06 PM
19-80, blind crippled or crazy, if they can't walk, wheel em in.

wux Joined Wed 07/29/09 Posts: 7426	Fri 01/27/12 06:08 PM
What's your preferred age range for dating? I have never really considered dating anyone more than 5 years younger than me, but I wonder if I am eliminating too many people. I mean, if one of my best friends can be in a relationship with someone so much younger and make it work...maybe. I just worry that there are too many stages in life and if two people are not in those same stages it could cause a lot of problems. It so depends on the person. Some guys are men at 25 and some guys are boys at 67. It just so depends. The mystery deepens... coz some women prefer boys, some prefer men, some prefer the boy inside the man, some prefer the man inside the boy.

Spidercmb Joined Fri 04/27/07 Posts: 13137	Fri 01/27/12 06:09 PM
No.. No.. No.. you specifically laid out 3 possibilities. You can't start making things up now.. "If you assumed that those 10 couples were father and daughter, I submit that you would be right more than 50% of the time." "they are dating" "If you generally think that people don't publicly cheat, you might assume that they are married to one another." 1. Father/daughter 2. Dating 3. Married Those are the 3 potential outcomes from your original post. Mathematically your more than 50% correct that these couples are father and daughter is NOT probable.. You can write 5000 paragraphs explaining one hundred thousand new variables, but it doesn't change your original post that you accused me of dodging and not willing to admit your above 50% claim was correct.. You can go on with this charade, or you can admit that based on your original post and what it contained you are NOT correct.. Its that simple.. I'm sorry, I believe that I already explained this. The problem you have isn't in the number of possibilities, it's in the weighting. All of the possibilities are not equally probably. Here's an example: Everybody with two hands is either: a) right handed b) left handed c) ambidextrous The probability that someone is right handed is between 70-90%. So if you guessed that everyone you met was right handed, you would be right more than 50% of the time. It's the same in my hypothetical scenario, it's much more likely that the pair is father/daughter than either of the other two possibilities listed. Don't forget, we are talking about a couple with enough years between them for the male to be mistaken for the female's father. You have 10 sets of men and women sitting at a table together.. Older men Younger women. You assume all 10 are father/daughter. You see kissing.. You see wedding rings.. Dates unmarried couples. Married couples.. Law of Probability.. All 10 couples are independent variables.. The equation for this is.. P/A variable x P/B variable x P/C variable.. If you flip 1 coin and assume it will land heads up that is 1/2 or a 50% probability.. If you flip 2 coins and you assume they will both land heads up that is 1/2 x 1/2 = 1/4 or a 25% probability.. Assuming a man and a woman sitting at a table can be one of three things and you deduce that they are a father daughter that is 1 the assumed relationship/ 3 possible relationships.. That is 33%... I'm sorry, you are just wrong. I thought that the handedness example would make you see the error in your thinking. Maybe if you go back to that post and read it again, your error will become clear.

wux Joined Wed 07/29/09 Posts: 7426	Fri 01/27/12 06:20 PM
I don't really understand why people get bent out of shape about someone's age preferences. same here but i will say it creeps me out when i see guys with much younger women to me it sends a message n i tend to think they aint mature enough for a woman thier own age not sayin thats the case but more often than not it is likewise when a woman is old enough to be a guy grandmother thats creepy too I think I would feel embarassed being with a younger man. Can you imagine sitting in restaurant getting ready to order and the waiter/waitress asks "what is your son having?" I saw a couple that I mistaken for father and daughter which was what the poor waitress thought too while the man chewed her out. That's just it. That's what I would do. Something manly. Every time I was on a date with some substantially older woman, I made sure one or more of these things were in order: 1. I was constantly grabbing my date's ****. No waiter would think I was then her son; embarrassment in public tactfully avoided. 2. I would pay. No son ever pays for a meal for his mom outside of mother's day. I used to be a son, once, too, you know. 3. I would argue with the date, the woman, challenge her theories and philosophies, and expected her to do the same. This would never happen with any of my mothers and me. 4. Scream something to the effect, "you did not pack any condoms AGAIN???" Just to avoid the embarrassment of being caught out in a restaurant on a Friday night with my own mother. 5. Avoid words that would indicate filial relationship. Never say "mother", "son", "mommy", etc., even if she is your sugar mommy. 6. Use words, instead, that denote precognitioning of carnal knowledge of each other prior to the date. These are: "lover", "sweetheart", "hott momma", "you juicey devil of a babe", "eeccha oot", "pass the saltshaker, biiiitch", "moocow", etc.

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 06:24 PM
No.. No.. No.. you specifically laid out 3 possibilities. You can't start making things up now.. "If you assumed that those 10 couples were father and daughter, I submit that you would be right more than 50% of the time." "they are dating" "If you generally think that people don't publicly cheat, you might assume that they are married to one another." 1. Father/daughter 2. Dating 3. Married Those are the 3 potential outcomes from your original post. Mathematically your more than 50% correct that these couples are father and daughter is NOT probable.. You can write 5000 paragraphs explaining one hundred thousand new variables, but it doesn't change your original post that you accused me of dodging and not willing to admit your above 50% claim was correct.. You can go on with this charade, or you can admit that based on your original post and what it contained you are NOT correct.. Its that simple.. I'm sorry, I believe that I already explained this. The problem you have isn't in the number of possibilities, it's in the weighting. All of the possibilities are not equally probably. Here's an example: Everybody with two hands is either: a) right handed b) left handed c) ambidextrous The probability that someone is right handed is between 70-90%. So if you guessed that everyone you met was right handed, you would be right more than 50% of the time. It's the same in my hypothetical scenario, it's much more likely that the pair is father/daughter than either of the other two possibilities listed. Don't forget, we are talking about a couple with enough years between them for the male to be mistaken for the female's father. You have 10 sets of men and women sitting at a table together.. Older men Younger women. You assume all 10 are father/daughter. You see kissing.. You see wedding rings.. Dates unmarried couples. Married couples.. Law of Probability.. All 10 couples are independent variables.. The equation for this is.. P/A variable x P/B variable x P/C variable.. If you flip 1 coin and assume it will land heads up that is 1/2 or a 50% probability.. If you flip 2 coins and you assume they will both land heads up that is 1/2 x 1/2 = 1/4 or a 25% probability.. Assuming a man and a woman sitting at a table can be one of three things and you deduce that they are a father daughter that is 1 the assumed relationship/ 3 possible relationships.. That is 33%... I'm sorry, you are just wrong. I thought that the handedness example would make you see the error in your thinking. Maybe if you go back to that post and read it again, your error will become clear. I just gave you the equation for calculating probability with independent variables.. How is that possibly wrong? There is no mathematical relation between your hand example and the original post.. That would be like saying the couples could be father and daughter, father and daughter that are in an incestuous relationship or a couple that is dating. Obviously.. if I chose father and daughter I would have a probability of being 66% correct. It's absurd..

sweetestgirl11 Joined Fri 09/12/08 Posts: 30087	Fri 01/27/12 06:26 PM
It's absurd.. ^ this

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 06:31 PM
It's absurd.. ^ this Its mathematical trench warfare.. Neither side is going to relent.. It's the way men used to be.. Ruthless and Unforgiving..

sweetestgirl11 Joined Fri 09/12/08 Posts: 30087	Fri 01/27/12 06:34 PM Edited by sweetestgirl11 on Fri 01/27/12 06:34 PM
It's absurd.. ^ this Its mathematical trench warfare.. Neither side is going to relent.. It's the way men used to be.. Ruthless and Unforgiving.. well there are better things to do with all of that testosterone (in my opinion)

Spidercmb Joined Fri 04/27/07 Posts: 13137	Fri 01/27/12 06:42 PM
I just gave you the equation for calculating probability with independent variables.. How is that possibly wrong? There is no mathematical relation between your hand example and the original post.. That would be like saying the couples could be father and daughter, father and daughter that are in an incestuous relationship or a couple that is dating. Obviously.. if I chose father and daughter I would have a probability of being 66% correct. It's absurd.. Honestly, I don't think I can explain it more clearly. The problem is that you are giving each possibility equal weight. 1) Father/daughter 2) Husband/wife 3) Boyfriend/girlfriend These possibilities aren't equally likely. May-December relationships aren't very common. Saying it's equally likely that the couple is father/daughter as it is that they are husband/wife is absolutely ludicrous. You are imagining a restaurant where all things are equally probably, no such place exists. It's much more likely for the couples to be father/daughter than the other possibilities. I understand where your confusion is coming from. You think "There are three possibilities, so each is 33% likely", but that is ignoring weighting of possibilities.

InvictusV Joined Sun 11/23/08 Posts: 5282	Fri 01/27/12 06:52 PM
It's absurd.. ^ this Its mathematical trench warfare.. Neither side is going to relent.. It's the way men used to be.. Ruthless and Unforgiving.. well there are better things to do with all of that testosterone (in my opinion) I just poured myself a drink and I will relax..